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Author Question: Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H2O. (Read 186 times)

Ebrown

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  • Posts: 567
on: Nov 18, 2019

Question 1

Determine the molality of a solution prepared by dissolving 0.500 moles of CaF2 in 11.5 moles H2O.
◦ 4.14 mol kg-1
◦ 1.88 mol kg-1
◦ 4.35 mol kg-1
◦ 5.31 mol kg-1
◦ 2.41 mol kg-1

Question 2

Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H2O.
◦ 0.818 mol kg-1
◦ 0.122 mol kg-1
◦ 0.220 mol kg-1
◦ 0.153 mol kg-1
◦ 0.454 mol kg-1
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by Ebrown on Nov 18, 2019

SVictor

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Ebrown

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

Mochi

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Reply 3 on: Yesterday
Gracias!

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