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Author Question: Calculate the pH of a solution formed by mixing 250.0 mL of 0.15 mol L-1 NH4Cl with 200.0 mL of 0.12 ... (Read 96 times)

sarasara

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  • Posts: 521
on: Nov 18, 2019

Question 1

Calculate the pH of a solution formed by mixing 250.0 mL of 0.15 mol L-1 NH4Cl with 100.0 mL of 0.20 mol L-1 NH3. The Kb for NH3 is 1.8 × 10-5.
◦ 9.25
◦ 8.98
◦ 9.53
◦ 9.13
◦ 4.74

Question 2

Calculate the pH of a solution formed by mixing 250.0 mL of 0.15 mol L-1 NH4Cl with 200.0 mL of 0.12 mol L-1 NH3. The Kb for NH3 is 1.8 × 10-5.
◦ 4.74
◦ 9.06
◦ 4.55
◦ 9.45
◦ 9.26
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by sarasara on Nov 18, 2019

mcni194

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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sarasara

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

cdmart10

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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