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Author Question: The observation that 4.0 g of hydrogen reacts with 32.0 g of oxygen to form a product with O:H mass ... (Read 49 times)

Hungry!

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on: Feb 15, 2020

Question 1

The observation that 15.0 g of hydrogen reacts with 120.0 g of oxygen to form 135.0 g of water is evidence for the law of
◦ energy conservation.
◦ multiple proportions.
◦ definite proportions.
◦ mass conservation.

Question 2

The observation that 4.0 g of hydrogen reacts with 32.0 g of oxygen to form a product with O:H mass ratio = 8:1, and 6.0 g of hydrogen reacts with 48.0 g of oxygen to form the same product with O/H mass ratio = 8:1 is evidence for the law of
◦ multiple proportions.
◦ mass conservation.
◦ energy conservation.
◦ definite proportions.
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by Hungry! on Feb 15, 2020

nikmaaacs

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Hungry!

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Reply 2 on: Feb 15, 2020
Wow, this really help

kilada

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Reply 3 on: Yesterday
Excellent

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