Question 1
Arrange in order from the smallest to the largest bond angle: CCl
3+, NF
3, NH
4+, XeBr
4.
◦ NF
3, NH
4+, XeBr
4, CCl
3+◦ XeBr
4, NF
3, NH
4+, CCl
3+◦ XeBr
4, NH
4+, NF
3, CCl
3+◦ CCl
3+, NF
3, NH
4+, XeBr
4Question 2
The VSEPR model predicts the H—B—H bond angle in BH
3 to be
◦ 90°.
◦ less than 120° but greater than 109.5°.
◦ 120°.
◦ 109.5°.