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Author Question: According to the balanced equation shown below, 1.00 mole of oxalic acid, H2C2O4, reacts with ... (Read 109 times)

serike

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on: Feb 15, 2020

Question 1

What is the reduction half reaction for the following chemical reaction in a basic solution?

ClO-(aq) + Cr(OH)4-(aq) → CrO42-(aq) + Cl-(aq)


◦ Cr(OH)4-(aq) + 4 OH-(aq) → CrO42-(aq) + 4 H2O(l) + 3e-
◦ ClO-(aq) + 2 H+(aq) + 2e- → Cl-(aq) + H2O(l)
◦ Cr(OH)4-(aq) → CrO42-(aq) + 4 H+(aq) + 3e-
◦ ClO-(aq) + H2O(l) + 2e- → Cl-(aq) + 2 OH-(aq)

Question 2

According to the balanced equation shown below, 1.00 mole of oxalic acid, H2C2O4, reacts with ________ moles of permanganate ion, MnO4-.

5 H2C2O4(aq) + 2 MnO4-(aq) + 6 H+(aq) → 10 CO2(g) + 2 Mn2+(aq) + 8 H2O(l)


◦ 2.00
◦ 0.400
◦ 1.00
◦ 2.25
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by serike on Feb 15, 2020

Laurenleakan

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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serike

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Reply 2 on: Feb 15, 2020
Wow, this really help

ashely1112

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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