Author Question: For the linear equation y = -4 - 4.6x, explain what the y-intercept and slope represent in terms of ... (Read 64 times)

Arii_bell · **on:** Apr 7, 2020

For the linear equation y = -4 - 4.6x, explain what the y-intercept and slope represent in terms of the graph of the equation.
◦ The y-intercept, b₀ = -4, gives the y-value at which the straight line y = -4 - 4.6x intersects the y-axis. The slope, b₁ = -4.6, indicates that the y-value decreases by 4.6 units for every increase in x of 1 unit.
◦ The y-intercept, b₀ = -4, gives the y-value at which the straight line y = -4 - 4.6x intersects the x-axis. The slope, b₁ = -4.6, indicates that the x-value decreases by 4.6 units for every increase in y of 1 unit.
◦ The y-intercept, b₀ = -4, gives the y-value at which the straight line y = -4 - 4.6x intersects the y-axis. The slope, b₁ = 4.6, indicates that the y-value increases by 4.6 units for every increase in x of 1 unit.
◦ The y-intercept, b₀ = -4.6, gives the y-value at which the straight line y = -4 - 4.6x intersects the y-axis. The slope, b₁ = -4, indicates that the y-value decreases by 4 units for every increase in x of 1 unit.

ngr69 · **Reply #1 on:** Apr 7, 2020

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