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Author Question: In a certain apportionment problem, State X has a standard quota of 48.9. The final apportionment to ... (Read 84 times)

Caiter2013

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on: May 5, 2020

Question 1

In a certain apportionment problem, State X has a standard quota of 73.9. The final apportionment to State X is 72 seats. This is called
◦ a lower-quota violation.
◦ an upper-quota violation.
◦ the Alabama paradox.
◦ the population paradox.
◦ none of these

Question 2

In a certain apportionment problem, State X has a standard quota of 48.9. The final apportionment to State X is 47 seats. Which of the following apportionment methods could have produced this result?
◦ Adams's method
◦ Jefferson's method
◦ Hamilton's method
◦ all of these
◦ none of these
Excursions in Modern Mathematics ¦ Tannenbaum ¦ 9th Edition
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Marked as best answer by Caiter2013 on May 5, 2020

sultansheikh

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Reply #1 on: May 5, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Caiter2013

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Reply 2 on: May 5, 2020
Wow, this really help

EAN94

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Reply 3 on: Yesterday
:D TYSM

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