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Author Question: To add 0.01 + 0.02 + ... + 1.00, what order should you use to add the numbers to get better accuracy? (Read 172 times)

sabina

  • Hero Member
  • *****
  • Posts: 563
on: May 6, 2020

Question 1

How many times is the println statement executed?

for (int i = 0; i < 10; i++)
for (int j = 0; j < i; j++)
​System.out.println(i * j)

◦ 100
◦ 45
◦ 20
◦ 10

Question 2

To add 0.01 + 0.02 + ... + 1.00, what order should you use to add the numbers to get better accuracy?
◦ Add 0.01, 0.02, ..., 1.00 in this order to a sum variable whose initial value is 0.
◦ Add 1.00, 0.99, 0.98, ..., 0.02, 0.01 in this order to a sum variable whose initial value is 0.
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Marked as best answer by sabina on May 6, 2020

Juro

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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sabina

  • Member
  • Posts: 563
Reply 2 on: May 6, 2020
YES! Correct, THANKS for helping me on my review

adf223

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  • Posts: 304
Reply 3 on: Yesterday
Great answer, keep it coming :)

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