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Author Question: The equation that solves a problem is . The problem is: (Read 126 times)

BRWH

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on: Aug 1, 2020
The equation that solves a problem is . The problem is:

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How far above its initial position does a rock travel in 2.0 s when thrown up from a point 40 m above the ground?

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How far below its initial position does a rock travel in 2.0 s when thrown up from a point 40 m above the ground?

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What is the position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground 2.0 s after it is released?

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What is the change in position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground 2.0 s after it is released?

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What is the position relative to the ground of a rock thrown up at 3.0 m/s from a roof 20 m above the ground if its maximum height is 33.6 m?
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Marked as best answer by BRWH on Aug 1, 2020

janeli1

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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BRWH

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Reply 2 on: Aug 1, 2020
Wow, this really help

at

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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