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Author Question: A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 turns through ... (Read 101 times)

ec501234

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on: Aug 1, 2020

Question 1

A wheel rotating about a fixed axis has an angular position given by θ = 3.0 − 2.0t3, where θ is measured in radians and t in seconds. What is the angular acceleration of the wheel at t = 2.0 s?

◦
−1.0 rad/s2

◦
−24 rad/s2

◦
−2.0 rad/s2

◦
−4.0 rad/s2

◦
−3.5 rad/s2


Question 2

A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 turns through 2.4 revolutions during a 2.0-s time interval. What is the angular velocity at the end of this time interval?

◦
9.5 rad/s

◦
9.7 rad/s

◦
9.3 rad/s

◦
9.1 rad/s

◦
8.8 rad/s
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by ec501234 on Aug 1, 2020

johnpizzaz

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ec501234

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Reply 2 on: Aug 1, 2020
Excellent

lindahyatt42

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Reply 3 on: Yesterday
:D TYSM

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