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Author Question: A pendulum bob of mass m is set into motion in a circular path in a horizontal plane as shown in the ... (Read 104 times)

kwoodring

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on: Aug 6, 2020

Question 1

A particle whose mass is 2.0 kg moves in the xy plane with a constant speed of 3.0 m/s along the direction . What is its angular momentum (in kg⋅m2/s) relative to the point (0, 5.0) meters?

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12

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11

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13

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14

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21


Question 2

A pendulum bob of mass m is set into motion in a circular path in a horizontal plane as shown in the figure. The square of the angular momentum of the bob about the vertical axis through the point P is



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m2gl3 sin4θ/cos θ

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m2gl3 sin3θ/cos θ

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m2gl3 sin2θ/cos θ

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m2gl3 sin θ/cos θ

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m2gl3 sin2θ
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by kwoodring on Aug 6, 2020

cassie_ragen

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kwoodring

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Reply 2 on: Aug 6, 2020
Wow, this really help

pangili4

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Reply 3 on: Yesterday
Gracias!

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