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Author Question: A parallel plate capacitor is charged to voltage V and then disconnected from the battery. Leopold ... (Read 158 times)

cabate

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on: Aug 6, 2020

Question 1

A capacitor of unknown capacitance C is charged to 100 V and then connected across an initially uncharged 60-μF capacitor. If the final potential difference across the 60-μF capacitor is 40 V, determine C.

◦
49 μF

◦
32 μF

◦
40 μF

◦
90 μF

◦
16 μF


Question 2

A parallel plate capacitor is charged to voltage V and then disconnected from the battery. Leopold says that the voltage will decrease if the plates are pulled apart. Gerhardt says that the voltage will remain the same. Which one, if either, is correct, and why?

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Gerhardt, because the maximum voltage is determined by the battery.

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Gerhardt, because the charge per unit area on the plates does not change.

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Leopold, because charge is transferred from one plate to the other when the plates are separated.

◦
Leopold, because the force each plate exerts on the other decreases when the plates are pulled apart.

◦
Neither, because the voltage increases when the plates are pulled apart.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by cabate on Aug 6, 2020

tashiedavis420

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cabate

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Reply 2 on: Aug 6, 2020
Great answer, keep it coming :)

nguyenhoanhat

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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