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Author Question: What value of Z (atomic number) and A (mass number) result in the following alpha decay? (Read 119 times)

lracut11

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on: Aug 10, 2020

Question 1

What is the disintegration energy (in MeV) associated with this spontaneous decay?



mNd = 143.910 083 u
mCe = 139.905 434 u
mHe = 4.002 603 u

1 u = 1.66 × 10−27 kg


◦
1.54

◦
2.37

◦
1.90

◦
4.13

◦
8.21


Question 2

What value of Z (atomic number) and A (mass number) result in the following alpha decay?



◦
Z = 92; A = 238

◦
Z = 91; A = 238

◦
Z = 90; A = 234

◦
Z = 93; A = 238

◦
Z = 88; A = 236
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by lracut11 on Aug 10, 2020

Anna

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Reply #1 on: Aug 10, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lracut11

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Reply 2 on: Aug 10, 2020
Gracias!

hramirez205

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Reply 3 on: Yesterday
Wow, this really help

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