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Author Question: Three bacteria are placed in a petri dish. The population will double every day. ... (Read 208 times)

azncindy619

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on: Feb 28, 2021
Solve the problem.

Three bacteria are placed in a petri dish. The population will double every day. The formula for the number of bacteria in the dish on day t is
N(t) = 3(2)t
where t is the number of days after the three bacteria are placed in the dish. How many bacteria are in the dish six days after the three bacteria are placed in the dish?
◦ 192
◦ 11
◦ 36
◦ 108
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by azncindy619 on Feb 28, 2021

joechoochoy

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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azncindy619

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Reply 2 on: Feb 28, 2021
Great answer, keep it coming :)

DylanD1323

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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