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Author Question: Hector borrows $2500 at a rate of 9% compounded quarterly. Find how much Hector ... (Read 195 times)

misspop

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on: Feb 28, 2021
Solve the problem.

Hector borrows $2500 at a rate of 9% compounded quarterly. Find how much Hector owes at the end of 3 years.

Use: A = Pntwhere:
A = final amount
P = $2500 (the amount borrowed)
r = 9% = 0.09 (the annual rate of interest)
n = 4 (the number of times interest is compounded each year)
t = 3 (the duration of the loan in years)
◦ $3591.64
◦ $2672.58
◦ $30,675.00
◦ $3265.12
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by misspop on Feb 28, 2021

fraziera112

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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misspop

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Reply 2 on: Feb 28, 2021
Wow, this really help

cassie_ragen

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Reply 3 on: Yesterday
:D TYSM

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