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Author Question: Given the heats of the following reactions:H(kJ)I.P4(s) + 6Cl2(g) 4PCl3(g)1225.6II.P4(s) + 5O2(g) ... (Read 39 times)

maegan_martin

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Given the heats of the following reactions:
 
 
ΔH°(kJ)
I.
P4(s) + 6Cl2(g) → 4PCl3(g)
–1225.6
II.
P4(s) + 5O2(g) → P4O10(s)
–2967.3
III.
PCl3(g) + Cl2(g) → PCl5(g)
–84.2
IV.
PCl3(g) + O2(g) → Cl3PO(g)
–285.7
Calculate the value of ΔH° for the reaction below:
              P4O10(s) + 6PCl5(g) → 10Cl3PO(g)


–110.5 kJ
–610.1 kJ
–2682.2 kJ
–7555.0 kJ
None of these is within 5% of the correct answer.


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Marked as best answer by maegan_martin on Mar 21, 2021

amynguyen1221

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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maegan_martin

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)


aruss1303

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Reply 3 on: Yesterday
Wow, this really help

 

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