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Author Question: For the reaction A Products, successive half-lives are observed to be 10.0 min and 40.0 min.The ... (Read 41 times)

ARLKQ

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on: Mar 21, 2021

Question 1

For the reaction 2N2O5(g) → 4NO2(g) + O2(g), the following data were collected:
 
t (minutes)
[N2O5] (mol/L)
 
0
1.24 × 10-2
 
10.
0.92 × 10-2
 
20.
0.68 × 10-2
 
30.
0.50 × 10-2
 
40.
0.37 × 10-2
 
50.
0.28 × 10-2
 
 
70.
0.15 × 10-2

​

The half-life of this reaction is approximately:

 
Reference: Ref 12-10

​

​


◦ 15 minutes
◦ 18 minutes
◦ 23 minutes
◦ 36 minutes
◦ 45 minutes

Question 2

For the reaction A → Products, successive half-lives are observed to be 10.0 min and 40.0 min. The reaction follows the integrated rate law.
Reference: Ref 12-13

​

​


◦ [A] = –kt + [A]0
◦ ln [A] = –kt + ln [A]0
◦ = kt +
◦ = kt +
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by ARLKQ on Mar 21, 2021

elyse44

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ARLKQ

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)

Animal_Goddess

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Reply 3 on: Yesterday
:D TYSM

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