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Author Question: The reaction 2A + 5B products is first order in A and first order in B. What is the rate law for ... (Read 69 times)

RYAN BANYAN

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on: Mar 21, 2021

Question 1

The reactants A and B are mixed, and the reaction is timed until a color change occurs. The data are as follows:
[A]
[B]
Time (s)
0.100
0.140
25
0.050
0.140
25
0.100
0.070
100

The order of the reaction in terms of B is


◦ 2.
◦ 1/2.
◦ 0.
◦ –1/2.
◦ 1.

Question 2

The reaction 2A + 5B → products is first order in A and first order in B. What is the rate law for this reaction?

◦ rate = k[A]2[B]5
◦ rate = k[A]1[B]2
◦ rate =k[A]1[B]1
◦ rate = k[A]5[B]2
◦ rate = k[A]2/7[B]5/7

​

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Marked as best answer by RYAN BANYAN on Mar 21, 2021

bpool94

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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RYAN BANYAN

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Reply 2 on: Mar 21, 2021
Excellent

recede

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Reply 3 on: Yesterday
Gracias!

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