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Author Question: Identify the Lewis acid, Lewis base, and Lewis acid-base adduct in the following equation: (C2H5)2O ... (Read 430 times)

audie

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on: Nov 18, 2019
Identify the Lewis acid, Lewis base, and Lewis acid-base adduct in the following equation:

(C2H5)2O + BF3 ⇌ (C2H5)2O:BF3

◦ (C2H5)2O is a Lewis acid, BF3 is a Lewis base, and (C2H5)2O:BF3 is a Lewis acid-base adduct.
◦ (C2H5)2O and BF3 are both Lewis acid-base adducts and (C2H5)2O:BF3 is a Lewis acid.
◦ (C2H5)2O is a Lewis acid-base adduct, BF3 is a Lewis acid, and (C2H5)2O:BF3 is a Lewis base.
◦ (C2H5)2O is a Lewis base, BF3 is a Lewis acid-base adduct, and (C2H5)2O:BF3 is a Lewis acid adduct.
◦ (C2H5)2O is a Lewis base, BF3 is a Lewis acid, and (C2H5)2O:BF3 is a Lewis acid-base adduct.
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Marked as best answer by audie on Nov 18, 2019

mirabriestensky

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Savroop Hara

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Reply #2 on: Feb 20, 2022
Thank You!


magana444

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Reply #3 on: Feb 20, 2022
thank you


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