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Author Question: If Ka for HCN is 6.15 1010, what is Kb for CN? Note: CN + H2O HCN + OH (Read 34 times)

imowrer

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on: Mar 21, 2021

Question 1

If an acid, HA, is 18.1% dissociated in a 1.0 M solution, what is the Ka for this acid?

◦ 2.2 × 10–1
◦ 3.3 × 10–2
◦ 1.8 × 10–1
◦ 2.5 × 101
◦ None of these are correct.

Question 2

If Ka for HCN is 6.15 × 10–10, what is Kb for CN–?

  Note: CN– + H2O HCN + OH–    


◦ 6.15 × 10–24
◦ 6.15 × 104
◦ 1.63 × 10–5
◦ 1.23 × 10–9
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by imowrer on Mar 21, 2021

missalyssa26

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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imowrer

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Reply 2 on: Mar 21, 2021
:D TYSM

pangili4

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Reply 3 on: Yesterday
Excellent

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