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Author Question: For a particular reaction the equilibrium constant is 0.0110 at 370.C and H is +16.0 kJ at 25C. ... (Read 20 times)

SAVANNAHHOOPER23

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on: Mar 21, 2021

Question 1

For a particular chemical reaction ΔH = 4.5 kJ and ΔS = –23 J/K. Under what temperature condition is the reaction spontaneous?

◦ When T< –196 K.
◦ When T< 196 K.
◦ The reaction is spontaneous at all temperatures.
◦ The reaction is not spontaneous at any temperature.
◦ When T> 196 K.

Question 2

For a particular reaction the equilibrium constant is 0.0110 at 370.°C and ΔH° is +16.0 kJ at 25°C. Assuming ΔH° and ΔS° are temperature independent, calculate ΔS° for the reaction.

◦ 5.75 J/K
◦ –5.75 J/K
◦ –12.6 J/K
◦ 12.6 J/K
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by SAVANNAHHOOPER23 on Mar 21, 2021

AaaA

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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SAVANNAHHOOPER23

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Reply 2 on: Mar 21, 2021
Wow, this really help

miss_1456@hotmail.com

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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