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Author Question: Find the standard equation of the circle with centre at (1, 3) which is tangent to the line 5x - 12y = 8. (Read 95 times)

jman1234

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on: May 26, 2021

Question 1

Find the point(s) on the curve  y = x2  such that the tangent lines to the curve at those points pass through  (2, -12).
◦ (-6,  6) and (-2, 4)
◦ (6, 36) and (2, 4)
◦ (6, 36) and (-2, 4)
◦ (6, -36) and (-2, 4)
◦ (-6, 36) and (-2, 4)

Question 2

Find the standard equation of the circle with centre at (1, 3) which is  tangent to the line 5x - 12y = 8.
◦ 2 + 2 = 8
◦ 2 + 2 = 8
◦ 2 + 2 = 9
◦ 2 + 2 = 9
◦ 2 - 2 = 1
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Marked as best answer by jman1234 on May 26, 2021

ansleighelindsey

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jman1234

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Reply 2 on: May 26, 2021
Wow, this really help

Liamb2179

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Reply 3 on: Yesterday
:D TYSM

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