Question 1
Solve the integral equation y(x) = 1 +

dt by reinterpreting it as an initial-value problem.
◦ y =

◦ y =

◦ y =

◦ y =

◦ y =

Question 2
Solve the initial-value problem y" + 2 = 0, y'(2) = 3, y(-1) = -4.
◦ y = -x
2 - x - 4
◦ y = -x
2 + 7x + 4
◦ y = -x
2 + 7x + 12
◦ y = -x
2 + 7x - 12
◦ y = -x
2 + x - 2