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Author Question: Solve the initial-value problem y" = 1 + (y')2, y'(0) = 1, y(0) = 0. (Read 128 times)

leo leo

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Question 1

Solve the initial-value problem  xy" + 3y' = 0,  y'(1) = 2,  y(1) = 3.
◦ y = 2 +
◦ y = 5 -
◦ y = 4 -
◦ y = 1 +
◦ y = 4 +

Question 2

Solve the initial-value problem  y" = 1 + (y')2,  y'(0) = 1,  y(0) = 0.
◦ y = -ln(sin(x) - cos(x))
◦ y = ln(sin(x) - cos(x))
◦ y = ln(cos(x) - sin(x))
◦ y = -ln(cos(x) - sin(x))
◦ None of the above


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Marked as best answer by leo leo on May 27, 2021

cadimas

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leo leo

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Reply 2 on: May 27, 2021
Great answer, keep it coming :)


Dinolord

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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