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Author Question: Consider this graph.Determine which points on the graph are critical points and describe why each of ... (Read 74 times)

kodithompson

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on: Jun 16, 2021
Consider this graph.

Determine which points on the graph are critical points and describe why each of the points is a critical point.
◦ The points on the function at x = a, b, d, and e are critical points, because at x = a the first derivative does not exist and at x = b, d, and e the derivative is zero.
◦ Since the point at x = a is the only one for which the first derivative does not exist, this is the only critical point.
◦ The points on the function at x = a, b, d, and e are critical points, because the derivative is zero at each of these points.
◦ The only critical points are those at x = b, d, and e, because the derivative is zero only at these points.
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by kodithompson on Jun 16, 2021

laurnthompson

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kodithompson

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Reply 2 on: Jun 16, 2021
YES! Correct, THANKS for helping me on my review

frankwu0507

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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