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Author Question: The number of atoms in 10.0 g of CaCO3 (100.0 g/mol) is: (Read 35 times)

charchew

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on: Jul 8, 2021

Question 1

The name of which compound ends in -ite?
◦ HIO3
◦ Na2SO3
◦ H2SO3
◦ Na2CO3
◦ CaH2

Question 2

The number of atoms in 10.0 g of CaCO3 (100.0 g/mol) is:
◦ 18.1 × 1022 atoms
◦ 30.1 × 1022 atoms
◦ 6.02 × 1022 atoms
◦ 12.1 × 1023 atoms
◦ 12.1 × 1022 atoms
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by charchew on Jul 8, 2021

jasonq

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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charchew

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Reply 2 on: Jul 8, 2021
:D TYSM

strudel15

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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