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Author Question: Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide: Pb2+(aq) + 2 ... (Read 78 times)

elizabeth18

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on: Jul 8, 2021
Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide:

Pb2+(aq) + 2 I-(aq) → PbI2(s)

Lead iodide is virtually insoluble in water so that the reaction appears to go to completion. How many millilitres of 3.550 mol L-1 HI(aq) must be added to a solution containing 0.700 mol of to completely precipitate the lead?
◦ 2.54 × 10-3  mL
◦ 394 mL
◦ 197 mL
◦ 0.197 mL
◦ 0.394 mL
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by elizabeth18 on Jul 8, 2021

guyanai

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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elizabeth18

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Reply 2 on: Jul 8, 2021
Excellent

xiaomengxian

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Reply 3 on: Yesterday
Wow, this really help

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