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Author Question: Calculate the height of a column of liquid glycerol (d = 1.26 g/cm3), in meters, required to exert ... (Read 77 times)

jenna1

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on: Jul 8, 2021

Question 1

Calculate the height in meters of a column of liquid glycerol (d = 1.26 g/cm3) required to exert the same pressure as 760 mmHg (d = 13.60 g/cm3).
◦ 8.20 m
◦ 8.20 × 103 m
◦ 70.4 m
◦ 0.704 m
◦ 44.4 m

Question 2

Calculate the height of a column of liquid glycerol (d = 1.26 g/cm3), in meters, required to exert the same pressure as 4.91 m of water.
◦ 4.91 m
◦ 3.90 m
◦ 6.19 m
◦ 3.65 m
◦ 5.16 m
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by jenna1 on Jul 8, 2021

xiaomengxian

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jenna1

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)

Alyson.hiatt@yahoo.com

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Reply 3 on: Yesterday
Wow, this really help

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