Question 1
1674 J of heat are absorbed by 25.0 mL of NaOH (
d = 1.10 g/mL, specific heat = 4.10 J/g °C). The temperature of the NaOH goes up by how many degrees?
◦ 14.8 °C
◦ 18.0 °C
◦ 17.2 °C
◦ 14.2 °C
◦ 19.1 °C
Question 2
2 LiOH(s) → Li
2O(s) + H
2O(l) Δ
rH° = 379.1 kJ/mol
LiH(s) + H
2O(l) → LiOH(s) + H
2(g) Δ
rH° = -111.0 kJ/mol
2 H
2(g) + O
2(g) → 2 H
2O(l) Δ
rH° = -285.9 kJmol
Compute Δ
rH° in kJ/mol for 2 LiH(s) + O
2(g) → Li
2O(s) + H
2O(l)
◦ +125.2 kJ/mol
◦ -17.7 kJ/mol
◦ -128.8 kJ/mol
◦ -303.6 kJ/mol
◦ + 128.8 kJ/mol
