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Author Question: 100 mL of LiNO3(aq), 0.241 M is mixed with 240 mL of 0.618 M Ca(NO3)2(aq). What is the final ... (Read 39 times)

pragya sharda

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on: Jul 8, 2021

Question 1

0.25 mol of a nonvolatile, nonionic solute dissolved in 300 g of water (Kf = 1.86 °C m-1) will lower the freezing point how many degrees?
◦ 0.65 °C
◦ 2.2 °C
◦ 0.14 °C
◦ 1.6 °C
◦ 3.2 °C

Question 2

100 mL of LiNO3(aq), 0.241 M is mixed with 240 mL of 0.618 M Ca(NO3)2(aq). What is the final concentration of NO3-(aq) in the solution?
◦ 0.508 M
◦ 1.01 M
◦ 0.943 M
◦ 0.756 M
◦ 1.38 M
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by pragya sharda on Jul 8, 2021

k2629

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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pragya sharda

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Reply 2 on: Jul 8, 2021
:D TYSM

mammy1697

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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