For the reaction CO(g) + 3 H2(g) H2O(g) + CH4(g) , Kc = 190 at ...

[kwoodring]

Question 1

For the reaction below

CO(g) + 2 H₂(g) CH₃OH(g)

the equilibrium concentrations at 483 K are [CO] = 0.0753 M, [H₂] = 0.151 M, and [CH₃OH] = 0.0247 M. Calculate the value of K_c.
◦ 14.4
◦ 1.09
◦ 2.17
◦ 0.0694
◦ 0.917

Question 2

For the reaction CO(g) + 3 H₂(g) H₂O(g) + CH₄(g) , K_c = 190 at 1000 K. If a vessel is filled with these gases such that the initial concentrations are [CO] = 0.025 M, [H₂] = 0.045 M, [H₂O] = 0.025, M and [CH₄] = 0.046 M, in which direction will a reaction occur and why?
◦ toward products because Q_c = 0.17
◦ toward reactants because Q_c = 0.0029
◦ toward products because Q_c = 0.35
◦ toward reactants because Q_c = 505
◦ it is at equilibrium because Q_c = 1

[gcook]

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[kwoodring]

Gracias!

[EAN94]

Thanks for the timely response, appreciate it