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Author Question: What is the pH of the resulting solution if 45 mL of 0.432 mol L-1 aqueous methylamine, CH3NH2, is ... (Read 42 times)

KimWrice

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Question 1

What is the pH of the resulting solution if 25.00 mL of 0.10 mol L-1 aqueous acetic acid is added to 10.00 mL of 0.10 mol L-1 NaOH(aq)? Assume that the volumes of the solutions are additive. Ka = 1.8 × 10-5 for CH3COOH
◦ 9.43
◦ 9.08
◦ 4.92
◦ 4.57

Question 2

What is the pH of the resulting solution if 45 mL of 0.432 mol L-1 aqueous methylamine, CH3NH2, is added to 15 mL of 0.234 mol L-1 HCl(aq)? Assume that the volumes of the solutions are additive. Ka = 2.70 × 10-11 for CH3NH3+.
◦ 2.77
◦ 4.09
◦ 9.91
◦ 11.23


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Marked as best answer by KimWrice on Jul 8, 2021

spencer.martell

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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KimWrice

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Reply 2 on: Jul 8, 2021
Wow, this really help


lindahyatt42

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Reply 3 on: Yesterday
Gracias!

 

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