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Author Question: ApproveDisapproveCommuter8936Resident10322A small university conducts a random survey of 250 ... (Read 68 times)

olivia_rose

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ApproveDisapprove
Commuter8936
Resident10322

A small university conducts a random survey of 250 students to see if approval of a no-smoking policy on campus is somehow correlated with residency. The data are presented in the contingency table. Do the two variables appear to be dependent? Select the appropriate critical value (CV), test statistic (TS), and conclusion. (Useα= 0.01.)


CV = 6.6349, TS = 11.8897; the survey data provide sufficient evidence to accept the statement that residency status and approval are dependent.


CV = 6.6349, TS = 1.7688; the survey data do not provide sufficient evidence to reject the statement that residency status and approval are independent.


CV = 13.2767, TS = 4.4001; the survey data do not provide sufficient evidence to reject the statement that residency status and approval are independent.


CV = 6.6349, TS = 4.4001; the survey data do not provide sufficient evidence to reject the statement that residency status and approval are independent.



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Marked as best answer by olivia_rose on Feb 26, 2023

ealonif

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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olivia_rose

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Reply 2 on: Feb 26, 2023
Thanks for the timely response, appreciate it


juliaf

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Reply 3 on: Yesterday
Gracias!

 

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