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Author Question: Aluminum oxide can be reduced to aluminum metal using carbon, the other reaction product being ... (Read 27 times)

lrhoads

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on: Nov 5, 2023

Question 1

Aluminum metal has a specific heat of 0.900 J/g·°C. Calculate the amount of heat required to raise the temperature of 10.5 moles of Al from 30.5 °C to 225°C.
◦ 1.84 kJ
◦ 2.41 kJ
◦ 65.1 kJ
◦ 49.6 kJ
◦ 57.3 kJ

Question 2

Aluminum oxide can be reduced to aluminum metal using carbon, the other reaction product being carbon monoxide.  Determine the enthalpy change when 12.5 g of aluminum is produced by this method. [ΔH°f(carbon monoxide) = –110.5 kJ/mol; ΔH°f(aluminum oxide) = –1669.8 kJ/mol]
◦ 310 kJ
◦ 361 kJ
◦ 697 kJ
◦ 725 kJ
◦ 1504 kJ
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by lrhoads on Nov 5, 2023

latoyia.cook

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lrhoads

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

Zebsrer

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Reply 3 on: Yesterday
Wow, this really help

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