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Author Question: The equilibrium expression for the ionization of a weak monoprotic acid, HA, in water is: (Read 73 times)

C0DxHalo

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Question 1

The equilibrium expression for the hydrolysis of a weak base, A, in water is:
◦ Kb = [A]/[OH][H3O+]
◦ Kb = [OH][H3O+]/[A]
◦ Kb = [OH][HA]/[A]
◦ Kb = [OH][A]/[HA]
◦ Kb = [OH][HA]/[A][H3O+]

Question 2

The equilibrium expression for the ionization of a weak monoprotic acid, HA, in water is:
◦ Ka = [HA]/[OH][H3O+]
◦ Ka = [OH][H3O+]/[HA]
◦ Ka = [H3O+][HA]/[A]
◦ Ka = [H3O+][A]/[HA]
◦ Ka = [HA]/[H3O+][A]


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Marked as best answer by C0DxHalo on Nov 5, 2023

Burly

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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C0DxHalo

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Reply 2 on: Nov 5, 2023
Excellent


ebonylittles

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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