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Author Question: For the reaction CuS(s) + H2(g) H2S(g) + Cu(s), Gf (CuS) = 53.6 kJ/mol Gf (H2S) = 33.6 kJ/mol ... (Read 5 times)

markburs

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on: Nov 5, 2023
For the reaction CuS(s) + H2(g) H2S(g) + Cu(s),
         ΔG°f (CuS) = –53.6 kJ/mol
         ΔG°f (H2S) = –33.6 kJ/mol
         ΔH°f (CuS) = –53.1 kJ/mol
         ΔH°f (H2S) = – 20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by markburs on Nov 5, 2023

Deonnak85

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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markburs

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Reply 2 on: Nov 5, 2023
YES! Correct, THANKS for helping me on my review

pratush dev

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Reply 3 on: Yesterday
:D TYSM

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