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Author Question: Using the thermodynamic data provided below, calculate Ka1 for H2CO3(aq) at 25. Hf (kJ/mol)S ... (Read 5 times)

kmcolvin

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on: Nov 5, 2023

Question 1

Using the thermodynamic data provided below, calculate Ka for HCN(aq) at 25°.
         
 
ΔH°f (kJ/mol)
S° (J/K·mol)
H+(aq)
       0
        0
CN–(aq)
   151.0
   117.99
HCN(aq)
   105.4
   128.9
         


Question 2

Using the thermodynamic data provided below, calculate Ka1 for H2CO3(aq) at 25°.
         
 
ΔH°f (kJ/mol)
S° (J/K·mol)
H+(aq)
       0
        0
H2CO3(aq)
–698.7
   191
HCO3–(aq)
–691.11
     95.0
CO32– (aq)
–676.26
   –53.1
         
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by kmcolvin on Nov 5, 2023

dianagarcia

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kmcolvin

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

gcook

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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