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Author Question: The power factor to a motor is corrected and results in a 10 percent reduction in the motor line ... (Read 61 times)

yulisa3298

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on: Nov 27, 2023

Question 1

The power factor of an RL parallel circuit is equal to  


◦

apparent power times the true power.


◦

apparent power times the reactive power.


◦

true power divided by apparent power.


◦

apparent power divided by true power.



Question 2

The power factor to a motor is corrected and results in a 10 percent reduction in the motor line current. This will


◦

cause the motor speed to decrease.


◦

cause the motor speed to increase.


◦

cause the motor torque to decrease.


◦

have no effect on the motor operation.

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Marked as best answer by yulisa3298 on Nov 27, 2023

3ginamay

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Reply #1 on: Nov 27, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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yulisa3298

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Reply 2 on: Nov 27, 2023
Gracias!

kalskdjl1212

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Reply 3 on: Yesterday
:D TYSM

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