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Author Question: A few years ago the news magazine The Economist listed some of the stranger explanations used in the ... (Read 225 times)

Pineappleeh

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A few years ago the news magazine The Economist listed some of the stranger explanations used in the past to predict presidential election outcomes.
 
  These included whether or not the hemlines of women's skirts went up or down, stock market performances, baseball World Series wins by an American League team, etc. Thinking about this problem more seriously, you decide to analyze whether or not the presidential candidate for a certain party did better if his party controlled the house. Accordingly you collect data for the last 34 presidential elections. You think of this data as comprising a population which you want to describe, rather than a sample from which you want to infer behavior of a larger population. You generate the accompanying table:
 
   Joint Distribution of Presidential Party Affiliation and Party Control
   of House of Representatives, 1860-1996
 
   Democratic Control of House (Y = 0) Republican Control of House (Y = 1) Total
  Democratic President (X = 0) 0.412 0.030 0.441
  Republican President (X = 1) 0.176 0.382 0.559
  Total 0.588 0.412 1.00
 
  (a) Interpret one of the joint probabilities and one of the marginal probabilities.
  (b) Compute E(X). How does this differ from E(X = 0)? Explain.
  (c) If you picked one of the Republican presidents at random, what is the probability that during his term the Democrats had control of the House?
  (d) What would the joint distribution look like under independence? Check your results by calculating the two conditional distributions and compare these to the marginal distribution.
 
  What will be an ideal response?

Question 2

Calculate the following probabilities using the standard normal distribution. Sketch the probability distribution in each case, shading in the area of the calculated probability.
 
  (a) Pr(Z < 0.0)
  (b) Pr(Z  1.0)
  (c) Pr(Z > 1.96)
  (d) Pr(Z < 2.0)
  (e) Pr(Z > 1.645)
  (f) Pr(Z > 1.645)
  (g) Pr(1.96 < Z < 1.96)
  (h.) Pr(Z < 2.576 or Z > 2.576)
  (i.) Pr(Z > z) = 0.10; find z.
  (j.) Pr(Z < z or Z > z) = 0.05; find z.
  What will be an ideal response?



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owenfalvey

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Answer to Question 1

Answer:
(a) 38.2 percent of the presidents were Republicans and were in the White House while Republicans controlled the House of Representatives. 44.1 percent of all presidents were Democrats.
(b) E(X) = 0.559. E(X = 0) = 0.701. E(X) gives you the unconditional expected value, while E(X = 0) is the conditional expected value.
(c) E(X) = 0.559 . 55.9 percent of the presidents were Republicans. E(X = 0) = 0.299 . 29.9 percent of those presidents who were in office while Democrats had control of the House of Representatives were Republicans. The second conditions on those periods during which Democrats had control of the House of Representatives, and ignores the other periods.
(d)
Joint Distribution of Presidential Party Affiliation and Party Control of House of Representatives, 1860-1996, under the Assumption of Independence

Democratic Control of House (Y = 0) Republican Control of House (Y = 1) Total
Democratic President (X = 0) 0.259 0.182 0.441
Republican President (X = 1) 0.329 0.230 0.559
Total 0.588 0.412 1.00

Pr(X = 0 = 0) = = 0.440 (there is a small rounding error).
Pr(Y = 1 = 1) = = 0.411 (there is a small rounding error).

Answer to Question 2

Answer:
(a) 0.5000;
(b) 0.8413;
(c) 0.0250;
(d) 0.0228;
(e) 0.0500;
(f) 0.9500;
(g) 0.0500;
(h) 0.0100;
(i) 1.2816;
(j) 1.96.




Pineappleeh

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Reply 2 on: Jun 29, 2018
Excellent


jojobee318

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  • Posts: 298
Reply 3 on: Yesterday
:D TYSM

 

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