The relationship between a pure-strategy Nash equilibrium and a ...

[elizabeth18]

The relationship between a pure-strategy Nash equilibrium and a dominant-strategy equilibrium is that
 
  A) a dominant-strategy equilibrium is a special case of a pure-strategy Nash equilibrium.
  B) a pure-strategy Nash equilibrium is a special case of a dominant-strategy equilibrium.
  C) they are the same.
  D) there may not be a dominant-strategy equilibrium, but there always is a pure-strategy Nash equilibrium.
  E) they are mutually exclusive and exhaustive, in that a dominant-strategy equilibrium is the same thing as a mixed-strategy Nash equilibrium.

Question 2

Which of the following statements is NOT a reason that the cost of a college education is greater for the low-productivity group than for the high-productivity group?
 
  A) The wages they give up by going to college instead of working will tend to be higher for them.
  B) They may have to pay for tutoring services or other extra help to accomplish the same educational goal.
  C) They may have to take remedial classes, which would increase the length of time it takes to accomplish the same goal.
  D) Even if they take no remedial classes, they may have to spend more time studying for each class, and the value of their leisure time needs to be considered in the calculation.
  E) Based on previous signaling, such as from their high school grades or SATs, they may receive less merit-based financial assistance, and thus be under a greater financial strain during their college years.

[Danny Ewald]

Answer to Question 1

A

Answer to Question 2

A