Revenues reported last week from 25 randomly selected stores ...

[jho37]

Revenues reported last week from 25 randomly selected stores owned by an international clothing company averaged 59,540 with a standard deviation of 9,025. Interpreting the 95 confidence level: If we repeated this procedure with the same sample size, we would expect 95 of the resulting confidence intervals to contain the
  1.population mean revenue of the company's stores.
  2.sample mean value of 59,540.
  3.population mean value of 59,540.
  4.range of revenue of all the company's stores.

Question 2

Revenues reported last week from 25 randomly selected stores owned by an international clothing company averaged 59,540 with a standard deviation of 9,025. Assume all necessary data conditions are met. What is the 95 confidence interval for the mean revenues of all the company's stores?<--EndFragment--> span>
  1.59540  1805  (57735, 61345)
  2.59540  (0.95)(1805)  (57625.25, 61254.75)
  3.59540  (2.06)(1805)  (55821.7, 115361.7)
  4.It cannot be computed since we cannot find the multiplier t.

[Zebsrer]

Answer to Question 1

1

Answer to Question 2

3

[jho37]

TYSM

[epscape]

Gracias!