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Author Question: A researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. In ... (Read 197 times)

soccerdreamer_17

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on: Jul 25, 2018
A researcher wishes to estimate the proportion of adults in the city of Darby who are vegetarian. In a random sample of 1821 adults from this city, the proportion that are vegetarian is 0.044.
 
  Find a 99 confidence interval for the proportion of all adults in the city of Darby that are vegetarians.
  A) 0.0363 to 0.0517 B) 0.0392 to 0.0488 C) 0.0316 to 0.0564 D) 0.0138 to 0.0742

Question 2

A relative frequency distribution is given below for the size of families in one U.S. city.
 
  Size Relative frequency
  2 0.448
  3 0.211
  4 0.192
  5 0.089
  6 0.040
  7+ 0.020
 
  A family is selected at random.
 
  Find the probability that the size of the family is at least 3. Round approximations to three decimal places.
  A) 0.552 B) 0.659 C) 0.211 D) 0.341


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ebonylittles

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Reply #1 on: Jul 25, 2018
Answer to Question 1

C

Answer to Question 2

A


soccerdreamer_17

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Reply #2 on: Jul 25, 2018
Both answers were spot on, thank you once again


ebonylittles

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Reply #3 on: Jul 25, 2018
Great! Please up vote :D


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