Author Question: A cube of water ice (r = 0.917 103 kg/m3) is placed in mercury (r = 13.6 103 kg/m3), which is ... (Read 68 times)

B · **on:** Jul 28, 2018

A cube of water ice (r = 0.917 103 kg/m3) is placed in mercury (r = 13.6 103 kg/m3), which is liquid at 0 Celsius. If we ignore any possible melting of the ice cube and problems with the surface tension of mercury, the fraction of the ice cube that floats above the surface of the mercury is
a. 0.067 4.
b. 0.073 5.
c. 0.926.
d. 0.933.
e. 1.00.

Question 2

The water level in identical bowls, A and B, is exactly the same. A contains only water; B contains floating ice as well as water. When we weigh the bowls, we find that
a. WA < WB.
b. WA = WB.
c. WA > WB.
d. WB > WA if the volume of the ice cubes is greater than 1/9 the volume of the water.
e. WB > WA if the volume of the ice cubes is greater than 9 times the volume of the water.