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Author Question: Which of the above might best describe how soap behaves in a nonpolar solvent like turpentine? A) ... (Read 57 times)

geodog55

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on: Jul 29, 2018
Which of the above might best describe how soap behaves in a nonpolar solvent like turpentine?
 
  A) a
  B) b
  C) c
  D) d
  E) none of the above

Question 2

Fish don't live very long in water that has just been boiled and brought back to room temperature. Suggest why.
 
  A) There is now a higher concentration of dissolved CImage in the water.
  B) The nutrients in the water have been destroyed.
  C) Since some of the water was evaporated while boiling, the salts in the water are now more concentrated. This has a negative effect on the fish.
  D) The boiling process removes the air that was dissolved in the water. Upon cooling the water is void of its usual air content, hence, the fish drown.


CharlieArnold

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Reply #1 on: Jul 29, 2018
Answer to Question 1

Answer: C

Answer to Question 2

Answer: D


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geodog55

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Reply #2 on: Jul 29, 2018
Thank you!


CharlieArnold

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Reply #3 on: Jul 29, 2018
Always glad to help...


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