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Author Question: In a velocity selector having electric field E and magnetic field B, the velocity selected for ... (Read 143 times)

eruditmonkey@yahoo.com

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on: Jul 29, 2018
In a velocity selector having electric field E and magnetic field B, the velocity selected for positively charged particles is v = E/B. The formula is the same for a negatively charged particles.
 
  Indicate whether the statement is true or false

Question 2

A horizontal rod (oriented in the east-west direction) is moved northward at constant velocity through a magnetic field that points straight down. Make a statement concerning the potential induced across the rod.
 
  A)
 
  The west end of the rod is at higher potential than the east end.
  B)
 
  The east end of the rod is at higher potential than the west end.
  C)
 
  The top surface of the rod is at higher potential than the bottom surface.
  D)
 
  The bottom surface of the rod is at higher potential than the top surface.
  E)
 
  The potential is uniform across the rod.


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johnharpe

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Reply #1 on: Jul 29, 2018
Answer to Question 1

TRUE

Answer to Question 2

A


eruditmonkey@yahoo.com

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Reply #2 on: Jul 29, 2018
Both answers were spot on, thank you once again


johnharpe

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Reply #3 on: Jul 29, 2018
Great! Please up vote :D


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