When an object is placed 118 cm from a diverging thin lens, its ...

[meagbuch]

When an object is placed 118 cm from a diverging thin lens, its image is found to be 59 cm from the lens. The lens is removed, and replaced by a thin converging lens whose focal length is the same in absolute value as the diverging lens.
 
  This second lens is at the original position of the first lens. Where is the image of the object now?

Question 2

Light of wavelength 105 nm falls on a metal surface for which the work function is 5.00 eV. What is the minimum de
 
  Broglie wavelength of the photoelectrons emitted from this metal? (h = 6.626  10-34 J  s = 4.14  10-15 eV  s, c = 3.00  108 m/s, mel = 9.11  10-31 kg, 1 eV = 1.60  10-19 J)
  A) 0.24 nm
  B) 0.33 nm
  C) 0.47 nm
  D) 0.66 nm
  E) 0.94 nm

[Ptupou85]

Answer to Question 1

at infinity

Answer to Question 2

C

[meagbuch]

Excellent

[miss.ashley]

Gracias!