Author Question: A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at ... (Read 333 times)

ericka1

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A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so that its pendulum motion takes 3.00 s. How far from the center of the rod should the pivot be located?
 
  A) 7.98 cm
  B) 7.52 cm
  C) 8.73 cm
  D) 8.40 cm
  E) 23.4 cm

Question 2

The angle that a swinging simple pendulum makes with the vertical obeys the equation (t) = (0.150 rad) cos(2.85 rad/s)t + 1.66. (a) What is the length of the pendulum?
 
  A) 0.15 m
   B) 0.83 m
   C) 1.21 m
   D) 2.02 m
   E) It cannot be determined from the information given.
  (b) What is the mass of the swinging bob at the end of the pendulum?
   A) 2.85 kg
   B) 1.66 kg
   C) 0.454 kg
   D) 0.150 kg
   E) It cannot be determined from the information given.



CAPTAINAMERICA

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Answer to Question 1

C

Answer to Question 2

(a) C (b) E



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