A solution is 2.00 x 10-3 M Ba(NO3)2 and 0.0500 M KF. Given that ...

[colton]

A solution is 2.00 x 10^-3 M Ba(NO₃)₂ and 0.0500 M KF. Given that the K_sp of barium fluoride is 1.5 x 10^-6,
   
  a.
  Q_sp = 1 x 10^-4 so a precipitate will be observed.
   
  b.
  Q_sp = 2 x 10^-4 so a precipitate will be observed.
   
  c.
  Q_sp = 1 x 10^-6 so no precipitate will be observed
   
  d.
  Q_sp = 2 x 10^-5 so a precipitate will be observed.
   
  e.
  Q_sp = 5 x 10^-6 so a precipitate will be observed.

Question 2

Given that the K_sp for calcium fluoride CaF₂ is 3.2 x 10^-15, which of the following describes a solution that is 2.00 x 10^-5 M NaF and 2.00 x 10^-5 M Ca(NO₃)₂?
   
  a.
  Q = 4 x 10^-10 and there will be a precipitate formed
   
  b.
  Q = 8 x 10^-10 and there will be a precipitate formed
   
  c.
  Q = 8 x 10^-15 and there will be no precipitate formed
   
  d.
  Q = 1.3 x 10^-13 and there will be a precipitate formed
   
  e.
  Q = 8 x 10^-15 and there will be a precipitate formed

[Chou]

Answer to Question 1

e

Answer to Question 2

e

[colton]

Thanks

[Chou]

Welcome