Question 1
A .20-kg ice cube at 0.0°C has sufficient heat added to it to cause total melting, and the resulting water is heated to
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How much heat is added? For water
LF = 334,000 J/kg,
LV = 2.256 × 10
6 J/kg, the
c = 4.186 x 10
3 J/kg ∙ C.
◦ 81 kJ
◦ 14,000 kJ
◦ 59 kJ
◦ 130 kJ
Question 2
How much heat must be added to a 8.0-kg block of ice at -8°C to change it to water at
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The specific heat of ice is 2050 J/kg ∙ °C, the specific heat of water is 4186 J/kg ∙ °C, the latent heat of fusion of ice is 334,000 J/kg, and 1 cal = 4.186 J.
◦ 140 kcal
◦ 810 kcal
◦ 730 kcal
◦ 780 kcal
◦ 180 kcal