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Author Question: The figure shows a pV diagram for 0.0077 mol of ideal gas that undergoes the process 1 2 3. What ... (Read 43 times)

craiczarry

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on: Oct 11, 2019

Question 1

The figure shows a pV diagram for 0.0061 mol of ideal gas that undergoes the process 1 → 2 → 3. What is the pressure p2? (R = 8.31 J/mol ∙ K)



◦ 1.5 × 106 atm
◦ 4.9 atm
◦ 15 atm
◦ 4.9 × 105 atm

Question 2

The figure shows a pV diagram for 0.0077 mol of ideal gas that undergoes the process 1 → 2 → 3. What is the volume V3? (R = 8.31 J/mol ∙ K)



◦ 0 cm3
◦ 0 cm3
◦ 400 cm3
◦ 770 cm3
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Marked as best answer by craiczarry on Oct 11, 2019

mistyjohnson

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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craiczarry

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Reply #2 on: Oct 11, 2019
Excellent


mistyjohnson

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Reply #3 on: Oct 11, 2019
Great! Please up vote :D


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